struct Tree < int>>; bool ValsLess(Tree * t, int val) // post: return true if and only if all values in t are less than val
In part B, children try asked to enter IsBST playing with ValsLess and you may assuming that the same form ValsGreater is present. The answer was revealed less than:
bool IsBST(Tree * t) // postcondition: returns true if t represents a binary search // tree containing no duplicate values; // otherwise, returns false. < if>left,t->info) && ValsGreater(t->right,t->info) && IsBST(t->left) && IsBST(t->right); >
In advance of continuous try to influence/guess/cause on which the new difficulty from IsBST is actually for an enthusiastic n-node tree. Assume that ValsLess and ValsGreater both run-in O(n) returning to an enthusiastic letter-node forest.
A features with the exact same qualities
What is the asymptotic complexity of the function DoStuff shown below. Why? Assume that the function Combine runs in O(n) time when |left-right| = letter, i.e., when Combine is used to combine n elements in the vector a. More…
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